Solutions for a Class of the Higher Diophantine Equation

Article Preview

Abstract:

We studied the Diophantine equation x2+4n =y7.By using the elementary method and algebaic number theroy, we obtain the following concusions: (i) Let x be an odd number, one necessary condition which the equation has integer solutions is that 26n-1/7 contains some square factors. (ii) Let x be an even number, when n=7k(k≥1) , all integer solutions for the equation are (x,y)=(0,4k) ;when n=7k+3, all integer solutions are (x,y)=(±27k+3,22k+1); when n≡1,2,4,5,6 the equation has no integer solution.

You might also be interested in these eBooks

Info:

Periodical:

Pages:

2265-2269

Citation:

Online since:

July 2013

Authors:

Export:

Price:

Permissions CCC:

Permissions PLS:

Сopyright:

© 2013 Trans Tech Publications Ltd. All Rights Reserved

Share:

Citation:

[1] Lebsgue V A. Nouv. Amn. Math. 1850.

Google Scholar

[2] Nagell T,. Norsk Marem Forenings Skrifter Senel, (1921).

Google Scholar

[3] Na Li, Science Technology and Engineering. Vol. 11 (2011).

Google Scholar

[4] Li Gao, Yonggang Ma, Journal of southwest university for nationalities, Vol. 34 (2008).

Google Scholar

[5] Yinxia Ran, Journal of southwest university for nationalities, Vol. 38 (2012).

Google Scholar

[6] Yinxia Ran, Journal of YanAn university (natural science edition). Vol. 31 (2012).

Google Scholar

[7] Chengdong Pan, Chengpiao Pan, Algebraic number theory[M]. Shandong: Shandong university press, (2003).

Google Scholar